[Solved] First Letter to Appear Twice LeetCode Contest Problem

Given a string s consisting of lowercase English letters, return the first letter to appear twice.

Note:

• A letter a appears twice before another letter b if the second occurrence of a is before the second occurrence of b.
• s will contain at least one letter that appears twice.

First Letter to Appear Twice LeetCode Contest

Example 1:

Input: s = "abccbaacz"
Output: "c"
Explanation:
The letter 'a' appears on the indexes 0, 5 and 6.
The letter 'b' appears on the indexes 1 and 4.
The letter 'c' appears on the indexes 2, 3 and 7.
The letter 'z' appears on the index 8.
The letter 'c' is the first letter to appear twice, because out of all the letters the index of its second occurrence is the smallest.

Example 2:

Input: s = "abcdd"
Output: "d"
Explanation:
The only letter that appears twice is 'd' so we return 'd'.

Constraints:

• 2 <= s.length <= 100
• s consists of lowercase English letters.
• s has at least one repeated letter.

Solution

class Solution {
public:
    char repeatedCharacter(string s) {
        vector<bool> v(26);
        for(char c:s){
            if(v[c-'a'])return c;
			v[c-'a']=true;
        }
        return 'a';
    }
};

class Solution:
    def repeatedCharacter(self, s: str) -> str:
        occurences = defaultdict(int)
        for char in s:
            occurences[char] += 1
            if occurences[char] == 2:
                return char

class Solution {
    public char repeatedCharacter(String s) {
        Set<Character> seen = new HashSet<>(); 
        for(int i = 0; i < s.length(); i++){
            if(seen.contains(s.charAt(i))){
                return s.charAt(i); 
            }
            seen.add(s.charAt(i));
        }
        return '#'; 
    }
}

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