[Solved] Odd or Even with C++

Odd or Even: Mrs. Anitha , our favourite Maths teacher wanted to teach her students to check whether the given number is odd or even.
Write a program to accept an integer and to check whether the given number is odd or even using functions and pointers.

Note: Print the text “a is an odd number ” and “a is an even number” inside the function. 

Function Specification:
void oddoreven(int *a)
This function prints the text “a is an odd number” if the number is odd, else prints “a is an even number” if the number is even.

Input Format: 
The input consists of an integer.
 
Output Format: 
Refer to the sample input and output for formatting details.
[All text in bold corresponds to input and the rest corresponds to output.]

Sample Input and Output1:
Enter the number
5
5 is an odd number

Sample Input and Output2:
Enter the number
6
6 is an even number
Function Definitions:

Solution

#include <iostream>
using namespace std;

void oddoreven(int *a)
{
    if (*a % 2 == 0)
    cout << *a << " is an even number" << endl;
    else
    cout << *a << " is an odd number" << endl;
}


int main()
{
    int a;
    cout << "Enter the number" << endl;
    cin >> a;
    oddoreven(&a);
    return 0;
}

Happy Learning – If you require any further information, feel free to contact me.