[Solved] Rohit wants to give each of the N youngsters, 1 candy. Rohit is already carrying M candies

Rohit wants to give each of the N youngsters, 1 candy. Rohit is already carrying M candies. He goes to a candy store to purchase the remainder. There are exactly 4 candy-filled packets available in the shop.

Find the bare minimum of candy packets that Rohit must purchase to be able to distribute 1 candy to each of the N kids.

Explanation:

Test Case 1: Rohit has to purchase 2 more packets before he has enough sweets to provide 1 candy to each of the 20 kids.

Test Case 2: Rohit already has 100 candies, which is enough to provide 1 candy to each of the 10 kids, so he doesn’t need to buy any more packets.

Test Case 3: Rohit has to purchase 1 more packets to obtain 13 candies, which is enough to provide 1 candy to each of the 10 kids.

Test Case 4: The chef needs to purchase 3 more packets until he has 21 candies, which is enough to provide 1 candy to each of the 20 kids.

Input Format:

The first line of input will contain a single integer T, signifying the number of test cases.

The first and individual line of each test case comprises two values N and M — the number of children and the amount of candies Rohit already has.

Sample Input:

4
20 12
10 100
10 9
20 9

Constraints:

1 ≤ T ≤ 1000
1 ≤ N, M ≤ 100

Output Format:

Provide the least quantity of candy packets that Rohit needs to purchase for each test scenario in order to provide 1 candy to each of the N youngsters.

Sample Output:

2
0
1
3

Solution

C++

#include<bits/stdc++.h>
using namespace std;
void myfunc(){
int x,y;
cin>>x>>y;
if(y<x){
    int k;
    if((x-y)%4==0){
        k=(x-y)/4;
    }
    else{
        k=((x-y)/4)+1; 

    //sauravhathi
    }
    cout<<k<<endl;
}
else{
    cout<<0<<endl;
}

}

int main(){
    int n;
    cin>>n;
    for(int i=0;i<n;i++){
        myfunc();
    }
} 

Python

import math
t = int(input())
for i in range(t):
    inp = [int(i) for i in input().strip().split()]
    dif = inp[0] - inp[1]
    if dif > 0:
    #sauravhathi
        print(math.ceil(dif/4))
    if dif <= 0:
        print(0)

Java

import java.util.*;
import java.lang.*;
import java.io.*;

class Sauravhathi
{
    public static int findMinCandy(Double n, Double x) {
		if (x >= n)
			return 0;
		else {
    //sauravhathi
			return (int) Math.ceil((n - x) / 4);
		}
	}
    
	public static void main (String[] args) throws java.lang.Exception
	{
		Scanner scanner = new Scanner(System.in);
		int t = scanner.nextInt();
		while (t-- > 0) {
			Double n = scanner.nextDouble();
			Double x = scanner.nextDouble();
			System.out.println(findMinCandy(n, x));
		}
		scanner.close();
	}
}

C

#include<stdio.h>


int main()
{
    int test; scanf("%d",&test);
    while(test--)
    {
    	int x;
    	scanf("%d",&x);
    	int y;
    	scanf("%d",&y);
    	int main;
    	main=x-y;
    	if(main<=0){
            printf("0\n");
        }
        else if(main%4!=0){
            int z=(main/4)+1;
    //sauravhathi
            printf("%d\n",z);
        }
        else if(main%4==0){
            int w=(main/4);
            printf("%d\n",w);
        }
    }
    return 0;
}

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