[Solved] Sum of Odd and Even Digits with Java, C++, Python

Write a java program to calculate the sum of odd and even digits in a number. The input consists of a single integer ‘n’ which corresponds to the given number.The output must display the sum of odd numbers and even numbers.

Problem Constraints:
The datatype of integer must be long.
The file name must be Main.java

Sample Input and Output :

Enter the number
3924209420352
The sum of the odd digits are 29
The sum of the even digits are 16

Solution

import java.util.*;

class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Enter the number");
        long n = sc.nextLong();
        // sauravhathi
        long odd = 0;
        long even = 0;
        while(n!=0){
            long rem = n%10;
            if(rem%2==0){
                even = even + rem;
            }
            //sauravhathi
            else{
                odd = odd + rem;
            }
            n = n/10;
        }
        System.out.println("The sum of the odd digits are "+odd);
        System.out.println("The sum of the even digits are "+even);
    }
    // sauravhathi
}

#include <iostream>
using namespace std;

int main() {
    long n;
    cin >> n;
    long odd = 0;
    long even = 0;
    while(n!=0){
        long rem = n%10;
        if(rem%2==0){
            even = even + rem;
        }
        //sauravhathi
        else{
            odd = odd + rem;
        }
        n = n/10;
    }
    cout << "The sum of the odd digits are " << odd << endl;
    cout << "The sum of the even digits are " << even << endl;
    return 0;
}

n = int(input())
odd = 0
even = 0
// sauravhathi
while n != 0:
    rem = n % 10
    if rem % 2 == 0:
        even += rem
    else:
        odd += rem
    n //= n / 10
print("The sum of the odd digits are", odd)
// sauravhathi
print("The sum of the even digits are", even)

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